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If Aidan were 10 years older, he would be twice as old as Tucker. Is Aidan older than Tucker?

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by BTGmoderatorDC » Sat Aug 29, 2020 7:13 pm

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Answers

A

B

C

D

E

Stats

Difficulty—

If Aidan were 10 years older, he would be twice as old as Tucker. Is Aidan older than Tucker?

(1) Tucker is older than 8

(2) Aidan is younger than 100


OA B

Source: Veritas Prep
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Source: — Data Sufficiency |
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Re: If Aidan were 10 years older, he would be twice as old as Tucker. Is Aidan older than Tucker?

by gmatter2012 » Sun Aug 30, 2020 9:36 pm
BTGmoderatorDC wrote: ↑
Sat Aug 29, 2020 7:13 pm
 If Aidan were 10 years older, he would be twice as old as Tucker. Is Aidan older than Tucker?

(1) Tucker is older than 8

(2) Aidan is younger than 100


OA B

Source: Veritas Prep
There is a typo, in option B it should be younger than 10 NOT 100.
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Re: If Aidan were 10 years older, he would be twice as old as Tucker. Is Aidan older than Tucker?

by swerve » Mon Aug 31, 2020 2:50 pm
BTGmoderatorDC wrote: ↑
Sat Aug 29, 2020 7:13 pm
 If Aidan were 10 years older, he would be twice as old as Tucker. Is Aidan older than Tucker?

(1) Tucker is older than 8

(2) Aidan is younger than 100


OA B

Source: Veritas Prep
\(A + 10 = 2T \)

Question is
\(A > T \)
\(A > \dfrac{A+10}{2}\)
\(2A > A + 10\)
\(A > 10\)

And
\(A > T\)
\(2T - 10 > T\)
\(T > 10\)

So, the question is simplified:
\(A > 10\) OR \(T > 10\)

Statement 1: Tucker is older than \(8 \Rightarrow T > 8 \Rightarrow \)Insufficient to tell if \(T > 10 \quad\Large{\color{red}\chi}\)

Statement 2: Aidan is younger than \(10 \Rightarrow A < 10 \rightarrow\) directly answers our question \(\Large{\color{green}\checkmark}\)

Therefore, the correct answer is B
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