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--|-----------|--------------------------|----------------------------|---------|-----------
A(1) B C D(2)
If AC=BD and AB=BC/3 in the number line, then what is the value of C?
A. 11/10
B. 19/10
C. 29/15
D. 6/10
E. 9/5
OA is E
I am trying to solve this question but my approaches are not working. The following is one of the approach that i tried
Given AC = BD
Suppose AB = x, BC = y, CD = z
So, AB + BC = BC + CS
x + y = y + z
hence, x = z
Now given AB = BC/3 ---> x = y/3 = z
--|----------------------|--------------------------|------------------------|---------|-----------
A(1) y/3 B y C y/3 D(2)
Now, y/3 + y + y/3 = 1
5y/3 = 1
y = 3/5
As, question asks for C,
so C = (y/3 + y) / (5y/3) = 4/5.
Please let me know where i am making a mistake.
A(1) B C D(2)
If AC=BD and AB=BC/3 in the number line, then what is the value of C?
A. 11/10
B. 19/10
C. 29/15
D. 6/10
E. 9/5
OA is E
I am trying to solve this question but my approaches are not working. The following is one of the approach that i tried
Given AC = BD
Suppose AB = x, BC = y, CD = z
So, AB + BC = BC + CS
x + y = y + z
hence, x = z
Now given AB = BC/3 ---> x = y/3 = z
--|----------------------|--------------------------|------------------------|---------|-----------
A(1) y/3 B y C y/3 D(2)
Now, y/3 + y + y/3 = 1
5y/3 = 1
y = 3/5
As, question asks for C,
so C = (y/3 + y) / (5y/3) = 4/5.
Please let me know where i am making a mistake.
