Gmat_mission wrote: ↑Sun Apr 11, 2021 3:26 am
If a number between 10 and 50 (inclusive) at random, what is the probability that the tens digit is greater than ones digit?
A. \(\dfrac{31}{41}\)
B. \(\dfrac{10}{41}\)
C. \(\dfrac{14}{41}\)
D. \(\dfrac{27}{41}\)
E. \(\dfrac{11}{41}\)
Answer:
E
Solution:
The numbers between 10 and 50, inclusive, with the tens digits greater than the ones digit are: 10, 20, 21, 30, 31, 32, 40, 41, 42, 43, and 50. That is, there are 11 such numbers. Since there are 50 - 10 + 1 = 41 numbers in total, the probability of selecting a number with the tens digits greater than ones digit randomly is 11/41.
Answer: E
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