1) b<0
Doesn't provide any information about the number c. Hence, insufficient to answer the question.
Case 1: a<0<b, then c<a<0<b. For e.g. a = -1, b = 3 then c<-4(a-b)2) a-b > c
Case 2: 0<a<b, then c<a<b. For e.g. a = 2, b = 5 then c<-3(a-b)
Case 3: a<b<0, then we get two cases
For e.g. a = -4, b = -2 c<-2(a-b) or
If c = -6(<-2(a-b)), c<a<b<0.
If c = -3(<-2(a-b)), a<c<b<0.
So, we the number c may or may not be between a and b. Statement 2 is insufficient to answer the question.
a<b<0, then we get two cases1) + 2)
For e.g. a = -4, b = -2 c<-2(a-b) or
If c = -6(<-2(a-b)), c<a<b<0.
If c = -3(<-2(a-b)), a<c<b<0.
So, we the number c may or may not be between a and b. Statement 1+2 combined is insufficient to answer the question.
Answer E
