let's evaluate statement 1.
Let B's distinct prime factors be: 2, 3, 5
Now B can be 2*3*5, or it can be 2*2*3*5.. or basically anything in the form (2^x)*(3^y)*(5^z)

Now, we know a has all the prime factors that B has, as its own prime factors, and it can also have more.
A can be = 2*3*5, or 2*3*5*7, or 2*3*5*11

But is A a multiple of B? We cannot say, because if any of the prime factor's power in A is less than that in B, A won't be a multiple of B.
Example, B = 2*3*3*5*5, A = 2*3*5*7. Here, A has all prime factors that are in B, but it's not a multiple of B

Statement 2: If every factor of B is factor of A, we surely know A is multiple of B. Since, a number itself is also a factor of itself. 6 is a factor of 6, 10 is a factor of 10.. And if B is a factor of A, then A is definitely a multiple of B

So we just need statement 2 to confirm that A is multiple of B