For \(8^x\cdot 9^{2y}=81\cdot 2^{12y},\) let's factorize 8, 9, 81, and 12 into prime factors.
We have \(8^x\cdot 9^{2y}=81\cdot 2^{12y}\)
\(2^{3x}\cdot 3^{4y}=3^4\cdot 2^{12y}\)
=> 3x = 12y => x = 4y; and 4y = 4 => y = 1. Thus, x = 4y = 4*1 = 4.
The correct answer: B
Hope this helps!
-Jay
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