The Jock wrote:I am not sure about the source of this question, just saw it somewhere and tried to solve:

If 56<x<66, where x is an integer. x=?

1). When x is divided by 2, the remainder is 1
2). x+1 is divisible by 3.

Stmt 1) When x is divided by 2, the remainder is 1 -> x can be any odd number between 56-66.
such as, 57, 59, 61, 63, 65 so it is Insufficient

Stmt 2) x+1 is divisible by 3 -> x+1 could be 57, 60, 63. SO it is Insufficient
Combining (1) and (2) we get that x can be 59
So answer should be C

Please confirm if I am doing it right, because OA(No official source, so it could be wrong) is different.

The Jock wrote:Thanks a lot Rahul.

sk818020 wrote:OA is E?

The reason I think so is because;

1) Tells us x must be odd. So x could = 57, 59, 61, 63, or 65. Obviously insufficient.

2) Tells us that x plus 1 is divisible by three. So, x must be 1 less than nubmers divisible by 3. You could also rephrase this to say that when x is divided by three there is a remainder of 1.

The numbers divisible by three close to the range in this set are, 57, 60, 63, 66. Therefore x could equal, 59, 62, 65. Obviously insufficient.

Put them together and X could equal 59, or 65. Thus, together they are insufficient, E.

Is this the answer your book gave you?

THanks,

Jared