$$Let\ price\ of\ 1\ apple\ =\ a\ and\ 1\ banana\ =\ b$$
$$3a+4b\ =$1.37.....eqn1$$
$$5a+7b\ =$2.36.....eqn2$$
$$from\ equation\ 1;\ b=\frac{1.37-39}{4}$$
$$from\ equation\ 2;\ \frac{5a}{1}+\frac{7}{1}\left(\frac{1.37-39}{4}\right)=2.36$$
$$\frac{5a}{1}+\frac{9.59-21a}{4}=2.36$$
$$\frac{20a+9.59-21a}{4}=2.36$$
$$20a-21a+9.59=9.44$$
$$-a=9.44-9.59$$
$$a=0.15$$
$$b=\frac{1.37-3\left(0.15\right)}{4}=\frac{1.37-0.45}{4}$$
$$b=\frac{0.92}{4}=0.23$$
$$1a+1s=0.15+0.23=$0.38$$
$$Answer\ =\ A$$