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I need help to solve it.........

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by Alfred » Mon Jan 18, 2010 12:59 am
Hello friends

This is a question of arithmetic related to number problems, I have tried a lot to solve it but somehow I am unable to find out the correct answer.

If c is a +ve integer between 1 and 9, and n = 9,446 + c, then what is the value of c?
(1) n is divisible by 5.
(2) n is divisible by 9.
In the last paragraph, when n is divisible by 5, then "c" can be 4 or 9. In the next sentence it states, "if n is divisible by 9, you can add the digits and find what
the nearby multiples of 9 are. Which digits are you adding?

I had seen this question at www.testcircle.com/gmat in free GMAT sample videos, and there are more than 1000s of GMAT CAt test based questions in free sample videos.
Waiting for a good reply.
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by swati chaturvedi » Mon Jan 18, 2010 1:45 am
answer seems to be '4'

1. divisible by 5 -----

when 9446 is divided by 5,this leaves remainder of 1 and both 4 and 9 will satisfy the condition of n divisible by 5.

9446/5= 1889 1/5

2. divisible by 9-----

9446/9= 1049 5/9, with remainder of 5 and only 4 will satisfy this condition of n being divisible by 9.

Hope it is correct.
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by mun1shk » Mon Jan 18, 2010 2:39 pm
Alfred wrote:Hello friends

This is a question of arithmetic related to number problems, I have tried a lot to solve it but somehow I am unable to find out the correct answer.

If c is a +ve integer between 1 and 9, and n = 9,446 + c, then what is the value of c?
(1) n is divisible by 5.
(2) n is divisible by 9.
In the last paragraph, when n is divisible by 5, then "c" can be 4 or 9. In the next sentence it states, "if n is divisible by 9, you can add the digits and find what
the nearby multiples of 9 are. Which digits are you adding?

I had seen this question at www.testcircle.com/gmat in free GMAT sample videos, and there are more than 1000s of GMAT CAt test based questions in free sample videos.
Waiting for a good reply.
Thanks
Hi Alfred,

Remember the divisibility test of 9, if a number is given then you add up all the digits and see if the result is divisible by 9.
eg 72 = 7+2=9 so divisible by 9

for this question Ans should be D both statements will give answer 4.
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by Concordio » Fri Jan 22, 2010 11:55 pm
I think the answer is B. (1) is insufficient because it gives you two answers - 4 or 9. (2) only gives you 4 as a viable answer choice.
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by tata » Mon Jan 25, 2010 11:25 am
The question is a little confusing, does the question mean 1 and 9 ARE included? If it does then the answer is B, if 1 and 9 are EXCLUDED i.e 1<c<9 then the answer is D

mun1shk wrote:
Alfred wrote:Hello friends

This is a question of arithmetic related to number problems, I have tried a lot to solve it but somehow I am unable to find out the correct answer.

If c is a +ve integer between 1 and 9, and n = 9,446 + c, then what is the value of c?
(1) n is divisible by 5.
(2) n is divisible by 9.
In the last paragraph, when n is divisible by 5, then "c" can be 4 or 9. In the next sentence it states, "if n is divisible by 9, you can add the digits and find what
the nearby multiples of 9 are. Which digits are you adding?

I had seen this question at www.testcircle.com/gmat in free GMAT sample videos, and there are more than 1000s of GMAT CAt test based questions in free sample videos.
Waiting for a good reply.
Thanks
Hi Alfred,

Remember the divisibility test of 9, if a number is given then you add up all the digits and see if the result is divisible by 9.
eg 72 = 7+2=9 so divisible by 9

for this question Ans should be D both statements will give answer 4.
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by shashank.ism » Fri Feb 19, 2010 5:41 am
Alfred wrote:Hello friends

This is a question of arithmetic related to number problems, I have tried a lot to solve it but somehow I am unable to find out the correct answer.

If c is a +ve integer between 1 and 9, and n = 9,446 + c, then what is the value of c?
(1) n is divisible by 5.
(2) n is divisible by 9.
In the last paragraph, when n is divisible by 5, then "c" can be 4 or 9. In the next sentence it states, "if n is divisible by 9, you can add the digits and find what
the nearby multiples of 9 are. Which digits are you adding?

I had seen this question at www.testcircle.com/gmat in free GMAT sample videos, and there are more than 1000s of GMAT CAt test based questions in free sample videos.
Waiting for a good reply.Thanks
here n = 9446 + c
st.1: when 9446 is divided by 5 it will give remainder =1 (as last digit is 6)
so for 9446 + c to be divisible by 5, c+1 must be divisible by 5
also1< c<9 --> c= 4 -----------------(i)--------------sufficient

st.2: also when 9446 is divided by 5 it will give remainder =5 (as last sum of digit = 9+4+4+6 = 23)
so for 9446 + c to be divisible by 9, c+5 must be divisible by 9
also1=< c<=9 --> c= 4 -----------------(ii)--------------sufficient

Ans D
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by Mom4MBA » Fri Feb 19, 2010 8:42 am
Shashank is right here, actually the confusion here is in statement 1, because it is written between 1 and 9 that means 1 and 9 are not included.

so both the statements are sufficient alone, giving us answer D
Last edited by Mom4MBA on Fri Feb 19, 2010 10:08 am, edited 1 time in total.
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by shashank.ism » Fri Feb 19, 2010 10:04 am
Mom4MBA wrote:Shashank's is right here, actually the confusion here is in statement 1, because it is written between 1 and 9 that means 1 and 9 are not included.

so both the statements are sufficient alone, giving us answer D
Yeah that is what I meant to say that If its clearly written between 1 and 9 that means 1 and 9 are not included.
Also I have seen that whenever there is an inclusion of boundary values they always specify it in question or show it inform of mathematical expression so rest assured about it...
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by rohankelkar81 » Sat Feb 20, 2010 3:14 am
hi all,

I guess the answer is 'B'.... since that is precisely concludes the value of 'c'. n we dont need other hint for doing them.. it also takes care of optimization
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by shashank.ism » Sat Feb 20, 2010 5:08 am
rohankelkar81 wrote:hi all,

I guess the answer is 'B'.... since that is precisely concludes the value of 'c'. n we dont need other hint for doing them.. it also takes care of optimization
rohankelkar81 yeah B precisely concludes the value of C but A also gives the same value...
so you have to consider the option D which says" A and B are individually sufficient to ans he problem"
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