nk_81 wrote:If we have an equation (x+1) sqr = x sqr

We can get
x sqr + 2x + 1 = x sqr
hence x = -1/2

but why can't we perform a square root on both sides and end up with an equation

x + 1 = x

which doesn't make sense but technically is doable.... AM I MISSING SOME SIMPLE FUNDAMENTAL RULE?

squareroot of 4 is either +2 or -2

so square root of (x+1)^2 could be either +(x+1) or -(x+1). So you cannot simply take the positive roots on both sides of the equation and equate them.

nk_81 wrote:If we have an equation (x+1) sqr = x sqr

We can get
x sqr + 2x + 1 = x sqr
hence x = -1/2

but why can't we perform a square root on both sides and end up with an equation

x + 1 = x

which doesn't make sense but technically is doable.... AM I MISSING SOME SIMPLE FUNDAMENTAL RULE?

This is not the right forum for this question. Hopefully the moderators will move the topic.

I am using an example to point out the flaw :
25 = 25
=> (5)^2 = (-5)^2
If you take a square root both the sides and conclude 5 = -5, that is wrong.

Sqrt (x^2) = |x| (As square root should always be a non-negative value)
So using that if you'll solve the equation you have mentioned, it will reduce to :

|x+1| = |x|

And then you will get the same answer.

Ok...here is another fundamental doubt...
Q- If m and n are both positive, what is the value of m(sqr root n)?
1) mn/sqr root n = 10
2) m sqr.n/2=50

Now my approach says
1) sufficient - mn/sqr rt n can be written as
(m . sqr rt n. sqr rt n)/ sqr rt n ,
cancel sqr rt n from both nr and dr
and u have what the question is asking.
Am i right? because i find that this is what came to my mind first but this has not been described in Kaplan. I am doubting my approach.

nk_81 wrote:Ok...here is another fundamental doubt...
Q- If m and n are both positive, what is the value of m(sqr root n)?
1) mn/sqr root n = 10
2) m sqr.n/2=50

Now my approach says
1) sufficient - mn/sqr rt n can be written as
(m . sqr rt n. sqr rt n)/ sqr rt n ,
cancel sqr rt n from both nr and dr
and u have what the question is asking.
Am i right? because i find that this is what came to my mind first but this has not been described in Kaplan. I am doubting my approach.

That is correct - your reasoning is fine. 1) is sufficient; 2) insufficient - hence A.

Thank You

Actually stormier.... The answer is D, both are sufficient.

Take the square of the Question stem equation, you get (m sqr).n

Which is what you get with the second choice too.

nk_81 wrote:Actually stormier.... The answer is D, both are sufficient.

Take the square of the Question stem equation, you get (m sqr).n

Which is what you get with the second choice too.

Thanks for correcting me. D is the right answer, of course. I have a hard time reading the sqr and sqr root notations. I wish they added superscripts and subscripts tools.