piyush_nitt wrote:bluementor wrote:The point to note here is that we are dealing with consecutive integers. In a set of consecutive integers:
median = (first integer + last integer)/2
So from the given information:
Median(set S) = (b + a)/2 = 3b/4
a = b/2 (eq. 1)
Median(set Q) = (c + b)/2 = 7c/8
b = 3c/4 (eq. 2)
Using equations 1 and 2, we can solve for:
Median of set R = (a + c)/2
=(b/2 + c)/2
=(3c/8 + c)/2
=11c/16 . Choose C.
-BM-
Integers are "Consecutive intergers" not mentioned in the Q.
It could be anything Isn't it?
Please explain?
Actually, you are right. I have made an assumption that this set will not contain the same integers. What we are sure is that the question states "all integers from a to b inclusive", but I have assumed that these integers within this set are all unique to each other i.e. no repetitions.
For example, for set S, if a=4 and b=7, then set S is {4, 5, 6, 7} and I'm assuming it will not be {4, 4, 5, 6, 6, 6, 7}, etc.
If my assumption is right, then we are essentially dealing with consecutive integers. Otherwise, I'm not sure how to solve this problem.
-BM-
