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how to solve this

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by diebeatsthegmat » Tue Sep 28, 2010 7:24 am
mrinal2100 wrote:Image
the answer is C, right?
you draw a right triangle with angle A=90 circle
there are 9 points of x from -6 to 2 and 6 point of y from 4 to 9
thus for A we will have 9*6 ways to select A
because x of B and x is the same and the point y of B must be 5 because B must different from A right?
the same for C you will get x of C is (9-1)=8
total=9*6*5*8=C
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by diebeatsthegmat » Tue Sep 28, 2010 7:25 am
mrinal2100 wrote:Image
i will post the same question for you to practice if you find the answer is C you are correct
26. A right triangle ABC has to be constructed in the xy-plane so that the right angle is at A and AB is parallel to x-axis. The coordinates of A, B and C are to satisfy the inequalities -3 ≤ x ≤ 5 and 2 ≤ y ≤ 11 and x & y are integers. The number of different triangles that can be constructed with these properties are?
(A) 90
(B) 900
(C) 6480
(D) 8100
(E) 10000
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