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by analyst218 » Mon May 10, 2010 9:01 am
vlazareva wrote:Image
[/img]
C.
since area of equilateral is (t^2*sq root 3)/4
setting it equal to s^2 will give you t^2/s^2 = 4/(sq root 3)
which means t:s = 4:sq rt3.
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by clock60 » Mon May 10, 2010 9:11 am
vlazareva wrote:Image
[/img]
i got 2/3^1/4 -D

the area of triangle=(t^2*3^1/2)/4=s^2 as area of the triangle equal that of square
(t/s)^2=4/3^1/2
t/s=2/(3^1/4)
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by debmalya_dutta » Mon May 10, 2010 7:34 pm
IMO D because
area of equilateral triangle = sqrt(3)/4 * (t)^2
area of square = s^2
hence t/s = 2/(3^0.25)
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by sanju09 » Tue May 11, 2010 3:37 am
vlazareva wrote:Image
[/img]
We have an equilateral triangle of side t and a square of side s, such that

√3/4 × t^2 = s^2

Or t^2 : s^2 = 4 : √3

Or t : s = [spoiler]2 : 4th root of 3

D, alright toothpastepromoter?[/spoiler]
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