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how much does A have?

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Re: how much does A have?

by mim3 » Mon Sep 08, 2008 2:20 pm
[quote="ddm"]A has $18 more than what B & C together would have had if both B and C had 1/4 of what A has. How much does A have?

(A) 20

(B) 48

(C) 32

(D) 36

(E) 40[/quote]


I solved this by working backwards and plugging in the answer choices to make the equation work. If B & C BOTH have a quarter of what A has, find those values first. Then, we know that (B + C) + 18= A.
So, if we choose D)36...
1/4 of 36 = 9
(9 + 9) + 18= 36 which is what we were looking for.

So, I'd say the answer is D. OA?
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by ddm » Mon Sep 08, 2008 2:28 pm
OA-D
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by Stockmoose16 » Tue Sep 09, 2008 5:10 pm
ddm wrote:OA-D
Is there any way to do this algebraically?
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by LSB » Tue Sep 09, 2008 5:19 pm
If B & C have 1/4 A then

B = 1/4A
C = 1/4A

1/4A + 1/4A + 18 = A
1/2A + 18 = A
18 = 1/2A
A = 36
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by glorydefined » Mon Sep 28, 2009 11:46 pm
gawd damn it!!! I got the whole question wrong... :x
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hmm

by JeffB » Tue Sep 29, 2009 8:50 am
don't really like the wording of the question.

I tried B + C = 1/4A first

then tried

B = 1/4A
C = 1/4A

Came up with 36
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by rajiishere » Tue Sep 29, 2009 8:57 am
I tried like this:
A = B+C+18
B = A/4
C = A/4
So, A = A/4 + A/4 + 18
= A/2 + 18
2A = A + 36
which is A = 36
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