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How many positive three digit integers contain atleast two 7

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How many positive three digit integers contain atleast two 7

by melguy » Tue Nov 22, 2016 7:39 pm
Please help me with this question. This is just a twist to an original question I got from GMATPrepNow videos so unfortunately answer choices are not available. I just twisted the question to clear out concepts.

How many positive three digit integers contain at least two 7's?

Step 1 : I listed all the possibilities
Step 2: I listed all possibilities that break the restriction (e.g 111, 222 i.e. dont have two 7's)

When adding up the answer seems to be incorrect :|

Please help with what am I missing?

Thanks
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by MartyMurray » Tue Nov 22, 2016 11:12 pm
First let's get the correct answer.

There is one positive three digit integer that contains three 7's, 777.

Now for the ones that contain two 7's.

We could start with 77.

Digits: 7 7 9 Possible Ones Digits We already used 777. So 7 cannot be a ones digit.

We could split the 7's.

Digits: 7 9 Possible Tens Digits 7

We could end with 77.

Digits: 8 Possible Hundreds Digits 7 7

Total Three Digit Numbers That Include At Least Two 7's = 1 + 9 + 9 + 8 = 27

Now let's consider what you did.

Hmm. I see that you considered the numbers with one 7 among their digits, but aren't there other three digit numbers that don't have at least two 7's, melguy?
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by melguy » Wed Nov 23, 2016 2:21 am
Sorry Marty I am really horrible with Counting and Probability questions. After a lot of work I could just grasp the basics and am really struggling with these 2 topics. I am thinking of maybe skipping anything that comes unless of course it's very basic!
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by MartyMurray » Wed Nov 23, 2016 4:09 am
melguy wrote:Sorry Marty I am really horrible with Counting and Probability questions. After a lot of work I could just grasp the basics and am really struggling with these 2 topics. I am thinking of maybe skipping anything that comes unless of course it's very basic!
melguy, what you missed doesn't have much to do with permutations. You did the permutations work that you did JUST RIGHT. However, you left out an entire category of integers.

With that in mind, figure out what you other category you have to subtract, and in so doing train yourself to get this type of question right, as you CLEARLY CAN.
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