chocoswiss wrote:Hi
Sorry I still dont understand Why i cant do as below:
1S2J: 4*6*5
2S1J: 4*3*6
3S: 4*3*2
I somehow always end up reverting to the slot method
Since order doesn't matter, you need to do some dividing in order to account for the duplicate combinations:
1S2J = 4 * (6*5)/(1*2) = 60
2S1J = (4*3)/(1*2) * 6 = 36
3S = (4*3*2)/(1*2*3) = 4
60+36+4 = 100.
You also could use the slot method this way:
Total possible groups of 3 = (10*9*8)/(1*2*3) = 120
Total possible groups of 3 with only junior partners = (6*5*4)/(1*2*3) = 20
Total possible groups of 3 with at least 1 senior partner = 120-20 = 100.
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