What is the area of a triangle created by the intersections of the lines x=4, y=5, and y=−3/4x+20?
42
54
66
72
96
42
54
66
72
96
Hi shibsriz,
I'm going to offer a quick run-down of the "steps" to solve this problem so that you can attempt them on your own:
If you graph the 3 lines that are defined in this question, you'll end of up with a triangle. In addition, you know that it MUST be a right triangle because one line is horizontal (Y = 5) and one is vertical (X = 4). When a horizontal line and a vertical line "criss-cross", you end up with a 90 degree angle.
By graphing the third line: Y = (-3/4)X + 20, you'll have a diagonal line that completes the triangle. This line will help you calculate the base and the height, so you can calculate the area of the triangle.
GMAT assassins aren't born, they're made,
Rich
