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How can you solve this problem faster?

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Re: How can you solve this problem faster?

by farooq » Mon Mar 02, 2009 2:56 am
oxvt wrote:1001^2-999^2 / 101^2-99^2

A) 10
B) 20
C) 40
D) 80
E) 100
I took 1 min :(

use formula a^2 - b^2 = (a+b)(a-b)

(1001-999)(1001+999)/(101-99)(101+99) =10.
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Farooq Farooqui.
London. UK

It is your Attitude, not your Aptitude, that determines your Altitude.
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by krisraam » Mon Mar 02, 2009 6:39 am
(a+b)^2 + (a-b)^2 = 4ab

(1000 + 1)^2 + (1000 -1)^2 = 4*1000 *1

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raama
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by kamu » Mon Mar 02, 2009 8:15 am
krisraam wrote:(a+b)^2 + (a-b)^2 = 4ab

(1000 + 1)^2 + (1000 -1)^2 = 4*1000 *1

Thanks
raama
I think you meant (a+b)^2 - (a-b)^2 = 4ab

and

(a+b)^2 + (a-b)^2 = 2(a^2 +b^2)
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