What is the value of x? (1) 3(x–1) = y+3x (2) (x+2)(y+3) = 0 Answer: E

Stmt I 3(x-1) = y+3x 3x-3 = y+3x y=-3 No way to find X INSUFF Stmt II (x+2)(y+3) = 0 Either x ix-2 or y is -3 or they both can be -2 and -3 INSUFF Stmt I and II together y=-3 Still we dont know if x is -2 or any other value INSUFF Choose E)

(1) 3(x–1) = y+3x 3x cancels. no info for X INSUF (2) (x+2)(y+3) = 0 X=-2 or y=-3 INSUF (1)+(2) Can not be solved for X because there is no X values in statement 1 Choose E

in stmt 1 we cant find value of x. Is it coz x can potentially have infinite values?? thanks

vittalgmat wrote:in stmt 1 we cant find value of x. Is it coz x can potentially have infinite values?? thanks Yes thats correct 3(x–1) = y+3x 3x - 3 = y + 3x y = -3 substitute value of y back in the equation 3x - 3 = -3 + 3x LHS = RHS Therefore, any value of x will satisfy the equation. Hence, we cannot get a single value of x.

Brent Hanneson wrote:What is the value of x? (1) 3(x–1) = y+3x (2) (x+2)(y+3) = 0 Answer: E Brent, GIVE US MORE NEW TOUGH QUESTIONS!!!! Your questions are very interesting. I solved all questions from your site

4meonly wrote:Brent Hanneson wrote:What is the value of x? (1) 3(x–1) = y+3x (2) (x+2)(y+3) = 0 Answer: E Brent, GIVE US MORE NEW TOUGH QUESTIONS!!!! Your questions are very interesting. I solved all questions from your site I second that!!! Yeah.. Brent pllllllllleeeeeeaaaaase give us new tough questions.. I love your your approach to solutions as well...

Thanks Brent!! For nice questions!!

This a good question. I have one question regarding stmt B. from B, we know x=-2 and y=-3 Are we discarding B, because there are 2 solns for the equations regardless of we have unique values of x and y? Cramya wrote: Stmt II (x+2)(y+3) = 0 Either x ix-2 or y is -3 or they both can be -2 and -3

I have one question regarding stmt B. from B, we know x=-2 and y=-3 Are we discarding B, because there are 2 solns for the equations regardless of we have unique values of x and y? Quote: Cramya wrote: Stmt II (x+2)(y+3) = 0 Either x ix-2 or y is -3 or they both can be -2 and -3 Actually, there are an infinite number of solutions to the equation (x+2)(y+3) = 0 Here are a few: y = -3 and x=7 y = -3 and x=-4 y = -3 and x=222 y = -3 and x=1,000,000 etc. If you plug in these values, it is true that (x+2)(y+3) = 0 Since x can have an infinite number of values, we can't definitively say what x is. I hope that helps.

schumi_gmat wrote:This a good question. I have one question regarding stmt B. from B, we know x=-2 and y=-3 Are we discarding B, because there are 2 solns for the equations regardless of we have unique values of x and y? Cramya wrote: Stmt II (x+2)(y+3) = 0 Either x ix-2 or y is -3 or they both can be -2 and -3 eqtn is satisifed if 1. x=-2, y=irrespective, or 2. y=-3, x=irrespective, or 3. x=-2 and y=-3 so, we dont know exact value of x ( from above, it may be -2 or any other value when y=-3) Insufficient