Problem Solving

Anne and Beth will participate in a sack race (In a sack race, people hop to reach the finish line). In the time that Anne takes 3 hops, Beth takes 4 hops but the distance covered by Anne in 4 hops is equal to distance covered by Beth in 5 hops. What is the ratio of Anne's speed: Beth's speed?

3 : 5
12 : 20
15 : 16
1 : 1
5 : 3

kop wrote:Anne and Beth will participate in a sack race (In a sack race, people hop to reach the finish line). In the time that Anne takes 3 hops, Beth takes 4 hops but the distance covered by Anne in 4 hops is equal to distance covered by Beth in 5 hops. What is the ratio of Anne's speed: Beth's speed?

3 : 5
12 : 20
15 : 16
1 : 1
5 : 3

time taken for 3 hops by Anne = time taken for 4 hops by Beth
3*ta = 4*tb
tb/ta = 3/4

distance covered in 4 hops of Anne = distance covered in 5 hops of Beth
4A = 5B
A/B = 5/4

Anne's speed = A/ta
Beth's speed = B/tb

Ratio = A/B * tb/ta
= 5/4 * 3/4
= 15/16

Choose C

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