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Honey/Orange Juice

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by harsh.champ » Thu Feb 18, 2010 11:47 pm
A sample of x litres from a container having a 60 litre mixture of honey and orange Juice containing honey and orange Juice in the ratio of 2 : 3 is replaced with pure honey so that the container will have honey and orange in equal proportions. What is the value of x?

(A) 6 litres
(B) 10 litres
(C) 12 litres
(D) 20 litres
(E) 24 litres

The OA is B.
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by ajith » Thu Feb 18, 2010 11:57 pm
harsh.champ wrote:A sample of x litres from a container having a 60 litre mixture of honey and orange Juice containing honey and orange Juice in the ratio of 2 : 3 is replaced with pure honey so that the container will have honey and orange in equal proportions. What is the value of x?

(A) 6 litres
(B) 10 litres
(C) 12 litres
(D) 20 litres
(E) 24 litres

The OA is B.
In the end there is 30 litres of honey and 30 liters of Orange juice

Initially there was 24 liters of honey and 36 liters of Orange juice


The quantity of honey that has to be increased = 6 Liters
If x liters of mixture is replaced by pure honey ; the quantity of honey increased = x-2/5x = 3/5x

3/5x =6
x = 10
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by thephoenix » Fri Feb 19, 2010 12:03 am
harsh.champ wrote:A sample of x litres from a container having a 60 litre mixture of honey and orange Juice containing honey and orange Juice in the ratio of 2 : 3 is replaced with pure honey so that the container will have honey and orange in equal proportions. What is the value of x?

(A) 6 litres
(B) 10 litres
(C) 12 litres
(D) 20 litres
(E) 24 litres

The OA is B.
SOLN=60
HONEY=24
ORANGE=36

X LT REPLACED WITH HONEY-----> SOLN=60-X+X=60
HONEY=24-2X/5 +X=24+3X/5

NOW AFTER REPLACMENT SOLN HAS 50:50 H AND O
THERFORE
60/2=24+3X/5
SOLVING X=10 LTS
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