Honey/Orange Juice

Expert replies

harsh.champ: Legendary Member; Posts: 1132; Joined: Mon Jul 20, 2009 3:38 amFollowed by: 6 members; Location: India; Thanked: 64 times; GMAT Score:760

by harsh.champ » Thu Feb 18, 2010 11:47 pm

A sample of x litres from a container having a 60 litre mixture of honey and orange Juice containing honey and orange Juice in the ratio of 2 : 3 is replaced with pure honey so that the container will have honey and orange in equal proportions. What is the value of x?

(A) 6 litres
(B) 10 litres
(C) 12 litres
(D) 20 litres
(E) 24 litres

The OA is B.

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Source: Beat The GMAT — Problem Solving | Thu Feb 18, 2010 11:47 pm

ajith: Legendary Member; Posts: 1275; Joined: Thu Sep 21, 2006 11:13 pmFollowed by: 2 members; Location: Arabian Sea; Thanked: 125 times

by ajith » Thu Feb 18, 2010 11:57 pm

harsh.champ wrote:A sample of x litres from a container having a 60 litre mixture of honey and orange Juice containing honey and orange Juice in the ratio of 2 : 3 is replaced with pure honey so that the container will have honey and orange in equal proportions. What is the value of x?

(A) 6 litres
(B) 10 litres
(C) 12 litres
(D) 20 litres
(E) 24 litres

The OA is B.

In the end there is 30 litres of honey and 30 liters of Orange juice

Initially there was 24 liters of honey and 36 liters of Orange juice

The quantity of honey that has to be increased = 6 Liters
If x liters of mixture is replaced by pure honey ; the quantity of honey increased = x-2/5x = 3/5x

3/5x =6
x = 10

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thephoenix: Legendary Member; Posts: 1560; Joined: Tue Nov 17, 2009 2:38 amFollowed by: 5 members; Thanked: 137 times

by thephoenix » Fri Feb 19, 2010 12:03 am

harsh.champ wrote:A sample of x litres from a container having a 60 litre mixture of honey and orange Juice containing honey and orange Juice in the ratio of 2 : 3 is replaced with pure honey so that the container will have honey and orange in equal proportions. What is the value of x?

(A) 6 litres
(B) 10 litres
(C) 12 litres
(D) 20 litres
(E) 24 litres

The OA is B.

SOLN=60
HONEY=24
ORANGE=36

X LT REPLACED WITH HONEY-----> SOLN=60-X+X=60
HONEY=24-2X/5 +X=24+3X/5

NOW AFTER REPLACMENT SOLN HAS 50:50 H AND O
THERFORE
60/2=24+3X/5
SOLVING X=10 LTS

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