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Hiker Walk : DS

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by vani_13in » Mon Sep 07, 2009 7:42 am
A hiker walked for two days. On the second thay the hiker 2 hours longer and at an average speed 1 mile per hour (mph) faster than he walked the first day. If during the two days he walked a total of 64 miles and spent a total of 18 hours walkingm what was his average speed on the first day?

A. 2 mph
B. 3 mph
C. 4 mph
D. 5 mph
E. 6 mph

[spoiler]OA: B[/spoiler]
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by tom4lax » Mon Sep 07, 2009 11:40 am
t + t + 2 = 18, so t = 8 (time on the first day)

r(8) + (r+1)(10) = 64

r18 = 54

r=3
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