Help! "Each Senior in a College Course wrote a Thesis. The lengths, in page, of those seniors' theses re summarized in the graph above. a. What is the least possible number of seniors whose theses were within six pages of the median length? [/img]

debmalya_dutta wrote:Help! "Each Senior in a College Course wrote a Thesis. The lengths, in page, of those seniors' theses re summarized in the graph above. a. What is the least possible number of seniors whose theses were within six pages of the median length? [/img] Seniors between: 0-9 : 1 10-19: 4 20-29: 6 30-39: 7 40-49: 2 total 20 seniors are present. Therefore 22 entries for pagecounts will exist We need to find out median length: When arranged in ascending order, median will be the average of the Highestnumber of pages between 20-29 and the lowest number of pages between 30-39 (because, median of 20 elements is average of 10th and 11th elements) Highest number of seniors whoes thesis is within 6 pages of median length would be : all seniors between 10-19 and all seniors between 20-29 =6+4 = 10 (edited and corrected) Whats the OA?

Praveen, Total number of seniors =20 Median =Highest-Lowest/20=49-9/20=2 Within 6 pages of the median length=8 1 people are with 8 pages[0-9] Please correct me if i am wrong.

debmalya_dutta wrote:Help! "Each Senior in a College Course wrote a Thesis. The lengths, in page, of those seniors' theses re summarized in the graph above. a. What is the least possible number of seniors whose theses were within six pages of the median length? [/img] Agreeing with Selango, median is 20. but students who are within 6 pages of 20 will include the students from 10-19 and 20-29, therefore i reached the answer of 4+6= 10 do we have the OA? Preet