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Help with function problem please.

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Newbie | Next Rank: 10 Posts
Posts: 2
Joined: Wed Jul 02, 2008 8:16 pm
by pancho » Thu Sep 18, 2008 8:08 pm
For all real numbers v, the operation v* is defined by the equation v^*= v-(V/3). if (V^*)^*=8, then v=

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27

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Junior | Next Rank: 30 Posts
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Location: INDIA

whats the OA?

by tishan » Thu Sep 18, 2008 8:30 pm
I think it is 27...
(v-v/3)-(v-v/3)/3=8
2v/3-2v/9
v=27
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by bluementor » Fri Sep 19, 2008 12:00 am
IMO B
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by pancho » Fri Sep 19, 2008 8:14 am
B is the correct answer. Can someone please show me the steps involved.

Thanks much.
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by philipja » Fri Sep 19, 2008 11:54 am
Here's how I did it

(V^*)^*=8

=> (v-(V/3))^* = 8 ---- statement 1

Let k = v-(V/3)

statement 1 can be re-written as

k^* = 8

=>k-(k/3) = 8
=> 3k - k = 24
=> 2k = 24
=> k =12
=> v-(V/3) =12

=> 3v - v = 36
=> 2v = 36
=> v = 18
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Re: Help with function problem please.

by Scott@TargetTestPrep » Sat Dec 05, 2020 3:24 pm
pancho wrote: ↑
Thu Sep 18, 2008 8:08 pm
 For all real numbers v, the operation v* is defined by the equation v^*= v-(V/3). if (V^*)^*=8, then v=

15
18
21
24
27

Thanks!
Solution:

We can let w = v*; thus, we have (v*)* = w* = 8. That is,

w - w/3 = 8

2w/3 = 8

w = 8 x 3/2 = 12

Now, we earlier defined w = v*, and since w = 12, we have w = v* = 12, or:

v - v/3 = 12

2v/3 = 12

v = 12 x 3/2 = 18

Answer: B

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