Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Help to resolve GMAT set

Problem Solving — algebra and arithmetic
Expert replies
by Xbond » Sun Feb 15, 2009 7:53 am
Hi there,

Could you help me to resolve this set of PS and DS ?
I am very interested by the method to resolve these

regards
You do not have the required permissions to view the files attached to this post.
Join the discussion
Source: — Quantitative Reasoning |

by DanaJ » Sun Feb 15, 2009 8:25 am
First off: I believe you should try posting fewer questions per post. You have 13 questions in the document provided. You will have very few people willing to spent the time/resources to answer all of your questions in one post.


Q1 (3 of 37).
(operation)9 * (operation)6 = 3*9*3 = 9*9 = 81. This means that (operation) of x = 81. You have two options: x is either odd or even.
a. x is odd means that (operation)x = 3x = 81. This means x = 27. This solution is consistent with the initial assumption that x is odd, so when you're taking the exam you just stop here and pick D.
Answer: D.


Q2 (4 of 37)
Notice that the ratio of water:concentrate is 3:1. This means that for 4x juice you need x concentrate. You want to prepare 200 6-ounce serving, meaning 200*6 = 12*100 ounces of juice.
4 ounces juice................1 ounce concentrate
12*100 ounces juice........12*100*1/4 ounces concentrate or 12*25 ounces concentrate.
Since you have your juice in 12 ounce cans, you will need 25 such cans.
Answer: A.


Q3 (7 of 37)
Let's start by analyzing the picture. Notice that the measurement of angle ADB = 180 - 2x. Now, the measurement of angle ABD = 180 - x - (180 - 2x) = x. This means that ADB is an isosceles triangle, with AD = BD.
Now, triangle BDC is isosceles as well, since both angles D and C have the same measurement. This means that BD = BC = AD
1 will therefore be sufficient since AD = BD = BC = 6
2 is insufficient since we do not know anything about lengths, only angles.
Answer: A.
Join the discussion

by cramya » Sun Feb 15, 2009 8:32 am
Actaully per the rules of this forum only one question is allowed per post. Like DanaJ pointed out u will get more reponses if u stuck to this format. Just a friendly suggestion.

Also browsing through your questions I see that most (may be even all) have been answered on this forum.

If u search by keywords u should be able to find. This way u dont wait for others to respond.


Regards,
CR
Join the discussion

by DanaJ » Sun Feb 15, 2009 8:45 am
Q4 (8 of 37)
Say d = number of dogs, b = number of birds, t = total number of pets in the store.
You get that 1/3*t = d and that 1/5*t = b.
1. tells us that 1/5t = 30, meaning that t = 5*30 = 150. This makes d = 1/3*150 = 50 dogs. So 1 is sufficient.
2. tells us that d = b + 20. Replace d and b and you get that t/3 = t/5 + 20. Subtract t/5 from both sides and you get that 2t/15 = 20, finally getting to t = 150. d will be 1/3*150 = 50, so 2 is sufficient as well.
Answer: D.


Q5 (9 of 37)
What we should do first is transform miles into kilometers, since we're actually working with kilometers. 10 miles = 16 kilometers and now we can get started:
1. Pei was walking with an average speed of less than 6.4 km/h. This means that he walked a maximum of 8.8 km in 2 hours, which is less than 16 km. So 1 is sufficient.
2. 9 mins/km means that he would spend 16*9 = 144 minutes for the 16 km, which is more than 2 hours. So 2 is sufficient as well.
Answer: D.


Q6 (10 of 37)
Each stmt offers the same type of info: an additional point. What you should know is that if you have the slope of a line and a point on the line, it is sufficient to establish the equation of the line, meaning that you can tell if a certain point is or is not on the specified line. So either stmt is sufficient. Let me use one of the stmts to prove this.
A line's equation is y = a*x + b, with a being the slope. Since l has a slope of 3/4, then this means that l's equation will be y = 3/4*x + b.
Now, stmt 1 tells us that (4, 4) is on line l, meaning that 4 = 3/4*4 + b. This helps us find b, which will be 1. This means that l's equation is y = 3/4*x + 1.
Now we can check if (-2/3, 1/2) is on line l. If it is, then 1/2 has to equal 3/4*(-2/3) + 1, which is true.
Answer: D.
Join the discussion

by DanaJ » Sun Feb 15, 2009 9:32 am
Q7 (11 of 37) - really cute one...
You are looking for (2 + 4 + 6 + ... + 20) - (1 + 3 + 5 + ... + 19) = x. My suggestion is to forget about the parenthesis and you get that:
x = 2 + 4 + ... + 20 - 1 - 3 - ... - 19.
You should notice that the difference between terms is exactly 1 in every case and pair things up, so it's easier:
x = (2 - 1) + (4 - 3) + (6 - 5) + .... + (20 - 19) = 1 + 1 + ... +1 - you have ten 1's, since there are 10 pairs of (even - odd) numbers.
Quick, simple and efficient: B


Q8 (12 of 37)
Notice that the conveyor belt is wrapped around exactly half of the circumference for each wheel. The rest of it is actually the distance between the centers of the wheels (= x). So you will have that 2x = 15 - 2*(2PiR^2/2) or that 2x = 15 - Pi (since R = diameter/2 = 1/2). This means that the distance you are looking for is (15 - Pi)/2.
Answer: A.


Q9 (15 of 37)
The info provided means that the 20th board counting from the top is the 15th counting from the bottom. You will have another 14 boards below this one, making the whole stack 34 boards high.
Answer: D.


Q10 (17 of 37)
We are trying to figure out the remainder of dividing n to 6.
1. tells us that n is a multiple of 5. This doesn't help much, except telling us that the last digit of n is either 5 or 0. Say n = 20; then the remainder will be 8. But if n = 25, the remainder will be 1. If n = 30, then the remainder will be zero. There is no way of telling what the remainder will be, so 1 is insufficient.
2. is sufficient, since 6 is a divisor of 12. If n is divisible by 12, then n is certainly divisible by 6 (since 12 = 2*6). This means that the remainder will be zero. 2 is sufficient.
Answer: B.

Q11 (18 of 37)
f(x) is provided in every case. We need to calculate f(1 - x) in every case and see if they are equal or not.
A. f(1 - x) = 1 - (1 - x ) = x - NO
B. f(1 - x) = 1 - (1 - x)^2 - NO, since you would have -2x in the way
C. f(1 - x) = (1 - x)^2 - x^2 - NO, not the same as f(x)
D. f(1 - x) = (1 - x)^2*x^2 - BINGO
Answer: D.
Join the discussion

by Xbond » Sun Feb 15, 2009 1:32 pm
Guys, Many thks for your prompt reply and your advice
Join the discussion