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100 points for $49 worth of Veritas practice GMATs FREE VERITAS PRACTICE GMAT EXAMS Earn 10 Points Per Post Earn 10 Points Per Thanks Earn 10 Points Per Upvote ## help neeeded plsss!!! ##### This topic has 3 expert replies and 3 member replies pls help me in ths arrangemnt arrange the following to solve 'd' interms of 'e' 3d - 7^2 / (4+5d) = e plssssssssss i ve an exam after a while & need to see the steps ASAP thanks marmar Newbie | Next Rank: 10 Posts Joined 11 Mar 2012 Posted: 5 messages First thing to notice is that d=-4/5 cannot be a solution. Then just solve.... 12d+15d^2 - 49 = 4e+5de 15d^2 + (12-5e)d + (-4e-49) = 0 Notice this is now in quadratic form, now just solve however you prefer to solve quadratics. Someone else can write out the details if necessary. I'm not an expert, but this does not seem like a gmat question... ### GMAT/MBA Expert GMAT Instructor Joined 21 Jan 2009 Posted: 3650 messages Followed by: 82 members Upvotes: 267 GMAT Score: 760 marmar29 wrote: pls help me in ths arrangemnt arrange the following to solve 'd' interms of 'e' 3d - 7^2 / (4+5d) = e plssssssssss i ve an exam after a while & need to see the steps ASAP thanks marmar If the bracket use is correct, and the original question is how it appears here, then following steps can be followed: 3d - 7^2 / (4+5d) = e (multiply both sides with 4 + 5 d) 3d (4 + 5 d) - 49 = e (4 + 5 d) {open the brackets} 12 d - 15 d^2 - 49 = 4 e + 5 e d (take every term to one side of ‘=’ so as to make the coefficient of d^2 positive) 15 d^2 + 5 e d - 12 d + 4 e + 49 = 0 15 d^2 + (5 e - 12) d + (4 e + 49) = 0 {this is a quadratic equation in d, use quadratic formula to solve for d} d = [- (5 e - 12) ± √ {(5 e - 12) ^2 - 4 X 15 X (4 e + 49)}]/ (2 X 15) Solve further if you please, these are the two values of d in terms of e. _________________ The mind is everything. What you think you become. –Lord Buddha Sanjeev K Saxena Quantitative Instructor The Princeton Review - Manya Abroad Lucknow-226001 www.manyagroup.com Free GMAT Practice Test How can you improve your test score if you don't know your baseline score? Take a free online practice exam. Get started on achieving your dream score today! Sign up now. Newbie | Next Rank: 10 Posts Joined 29 Feb 2012 Posted: 2 messages The Quadratic equation seems dubious to me. 3d - 7^2 / (4+5d) = e (multiply both sides with 4 + 5 d) 3d (4 + 5 d) - 49 = e (4 + 5 d) {open the brackets} Then: 12 d + 15 d^2 - 49 = 4 e + 5 e d 15 d^2 + 12 d - 5 e d - 49 - 4 e = 0 15 d^2 + d(12 - 5 e) - (49 + 4 e) = 0 {this is a quadratic equation in d, use quadratic formula to solve for d} @Sanju09 : Am I wrong in identifying anything? ### GMAT/MBA Expert GMAT Instructor Joined 21 Jan 2009 Posted: 3650 messages Followed by: 82 members Upvotes: 267 GMAT Score: 760 Vikash_Pradhan wrote: The Quadratic equation seems dubious to me. 3d - 7^2 / (4+5d) = e (multiply both sides with 4 + 5 d) 3d (4 + 5 d) - 49 = e (4 + 5 d) {open the brackets} Then: 12 d + 15 d^2 - 49 = 4 e + 5 e d 15 d^2 + 12 d - 5 e d - 49 - 4 e = 0 15 d^2 + d(12 - 5 e) - (49 + 4 e) = 0 {this is a quadratic equation in d, use quadratic formula to solve for d} @Sanju09 : Am I wrong in identifying anything? What did you identify in the first place? _________________ The mind is everything. What you think you become. –Lord Buddha Sanjeev K Saxena Quantitative Instructor The Princeton Review - Manya Abroad Lucknow-226001 www.manyagroup.com Free GMAT Practice Test How can you improve your test score if you don't know your baseline score? Take a free online practice exam. Get started on achieving your dream score today! Sign up now. Newbie | Next Rank: 10 Posts Joined 29 Feb 2012 Posted: 2 messages Considering the equation in the form: A d^2 + B d + C = 0 My Equation: 15 d^2 + d(12 - 5 e) - (49 + 4 e) = 0 A = 15 B = (12 - 5 e) C = - (49 + 4 e) Your Equation: 15 d^2 + (5 e - 12) d + (4 e + 49) = 0 A = 15 B = (5 e - 12) C = (49 + 4 e) Its just the values that we are getting different, I have no doubt or concern over the method you suggested. Thanks, Vikash ### GMAT/MBA Expert GMAT Instructor Joined 21 Jan 2009 Posted: 3650 messages Followed by: 82 members Upvotes: 267 GMAT Score: 760 Vikash_Pradhan wrote: Considering the equation in the form: A d^2 + B d + C = 0 My Equation: 15 d^2 + d(12 - 5 e) - (49 + 4 e) = 0 A = 15 B = (12 - 5 e) C = - (49 + 4 e) Your Equation: 15 d^2 + (5 e - 12) d + (4 e + 49) = 0 A = 15 B = (5 e - 12) C = (49 + 4 e) Its just the values that we are getting different, I have no doubt or concern over the method you suggested. Thanks, Vikash Oh I got your point, my work should have continued as… 3d (4 + 5 d) - 49 = e (4 + 5 d) {open the brackets} 12 d + 15 d^2 - 49 = 4 e + 5 e d (take every term to one side of ‘=’ keeping the coefficient of d^2 positive) 15 d^2 = 5 e d + 12 d = 4 e = 49 = 0 15 d^2 = (5 e - 12) d = (4 e + 49) = 0 {this is a quadratic equation in d, use quadratic formula to solve for d} d = [(5 e - 12) ± √ {(5 e - 12) ^2 + 4 X 15 X (4 e + 49)}]/ (2 X 15) Solve further if you please, these are the two values of d in terms of e. regards _________________ The mind is everything. What you think you become. –Lord Buddha Sanjeev K Saxena Quantitative Instructor The Princeton Review - Manya Abroad Lucknow-226001 www.manyagroup.com Free GMAT Practice Test How can you improve your test score if you don't know your baseline score? Take a free online practice exam. Get started on achieving your dream score today! 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