[quote="madsport"]Can someone help make sense of this for me?
The answer is[spoiler] A[/spoiler][/quote]
Well, I'm assuming that because they're different symbols, we're dealing with all different numbers. If that's the case:
1. star= 4.
Because we know that square is less than triangle, we know that the triangle is 3 and the square is 1. Sufficient
2. square= 1.
That doesn't give us anything. The other symbols could be any numbers. Insufficient.
So, it's A
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Help needed
Source: Beat The GMAT — Data Sufficiency |
I think the answer is C.
Lets rephrase the equation for ease.
We can write it as
a
+b
= c
In the first case where the total is 4. The options could be 2+2, 0+4, 4+0,1+3,3+1. Well but we know that a <c. We are left with 2 choices now , either it is 0+4, or 1+3. So choice A is insuffcient.
Choice B Says that a=1. By itself this choice would not help us.
But if we combine the 2 now we know the option 0+4 is out since we know a=1. hence the answer is C.
Lets rephrase the equation for ease.
We can write it as
a
+b
= c
In the first case where the total is 4. The options could be 2+2, 0+4, 4+0,1+3,3+1. Well but we know that a <c. We are left with 2 choices now , either it is 0+4, or 1+3. So choice A is insuffcient.
Choice B Says that a=1. By itself this choice would not help us.
But if we combine the 2 now we know the option 0+4 is out since we know a=1. hence the answer is C.
Given Triangle(T) > Square (S)
Since both are POSITIVE DIGITS (so 0 is not included) therefore
T can have values 2,3,4,5,6,7,8,9
and S can have values 1,2,3,4,5,6,7,8
1. star=4
T+S=4
The only values that satisfy this condition are T=3 and S=1.
Therefore sufficient.
2. S=1
T could be anything from 2-9.
Therefore insufficient.
Hence answer A
Since both are POSITIVE DIGITS (so 0 is not included) therefore
T can have values 2,3,4,5,6,7,8,9
and S can have values 1,2,3,4,5,6,7,8
1. star=4
T+S=4
The only values that satisfy this condition are T=3 and S=1.
Therefore sufficient.
2. S=1
T could be anything from 2-9.
Therefore insufficient.
Hence answer A
