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by vdemidoff » Wed Nov 11, 2009 11:31 am
All of the 200 engineers who work at a software company are to be assigned to work on either new product development or maintenance of old products. At least 60 percent of them request to work on new product development. If at least 65 percent of engineers are to be assigned to maintenance of old products, what is the least number of engineers who will not get their requested [/color]assignment?[/color]


HELP!!!!!!!!!!!
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Re: Help me

by heshamelaziry » Wed Nov 11, 2009 12:14 pm
vdemidoff wrote:All of the 200 engineers who work at a software company are to be assigned to work on either new product development or maintenance of old products. At least 60 percent of them request to work on new product development. If at least 65 percent of engineers are to be assigned to maintenance of old products, what is the least number of engineers who will not get their requested [/color]assignment?[/color]


HELP!!!!!!!!!!!
120 requested new project
130 go to old project.

Deduction: 80 don't want the new project. so 130 - 80 = 50


What is OA
Last edited by heshamelaziry on Wed Nov 11, 2009 4:24 pm, edited 3 times in total.
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Re: Help me

by KICKGMATASS123 » Wed Nov 11, 2009 3:58 pm
heshamelaziry wrote:
vdemidoff wrote:All of the 200 engineers who work at a software company are to be assigned to work on either new product development or maintenance of old products. At least 60 percent of them request to work on new product development. If at least 65 percent of engineers are to be assigned to maintenance of old products, what is the least number of engineers who will not get their requested [/color]assignment?[/color]


HELP!!!!!!!!!!!
120 requested new project
135 go to old project.

Deduction: 70 don't want the new project. so 135 - 70 = 65


IMO 50.. because 130 have to be placed in Maintanence regardless of their choice. So then we have 70 remaining that will be placed in New product dev't.

We have >= 120 engg wanting to work in New product dev't. However, to get the least number. we need to have the lowest.. which is 120-70 = 50..

Please let me know what the OA is!
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by heshamelaziry » Wed Nov 11, 2009 4:14 pm
What if the question asked for the maximum number. Would be different ?
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by vdemidoff » Thu Nov 12, 2009 9:00 pm
the answer is 50. but guys...I didn't get you meant. PLZZZZ give me details (but firts explain the task to me) :oops:
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Re: Help me

by Testluv » Thu Nov 12, 2009 10:47 pm
vdemidoff wrote:All of the 200 engineers who work at a software company are to be assigned to work on either new product development or maintenance of old products. At least 60 percent of them request to work on new product development. If at least 65 percent of engineers are to be assigned to maintenance of old products, what is the least number of engineers who will not get their requested [/color]assignment?[/color]


HELP!!!!!!!!!!!
Hi vdemidoff,

let's pretend there are 100 and not 200 engineers. We'll just have to be sure to remember to double our final answer.

There are two categories:
Product Development (PD)
Maintenance of Old Products (MO)

We have to MINIMIZE the number of engineers who get an assignment they did not request. That is the task.

At least 65 (of our 100) have to be assigned to MO.

But at least 60 of them requested PD; therefore, at most 40 did NOT request PD.

These 40, who did not request PD, can all go to MO. Then MO still needs 25 enginners assigned to it. We will have to draw these 25 from the (sixty) who requested PD.

Therefore, at least 25 will get an assignement they did not request.

We have to double this (remember there are 200 and not 100), so there will be at least 50 engineers who will get an assignment they did not request.


Because we had to find the least number of engineers who would get an assignment they did not request, we wanted to a) minimize the number who DID request an assignment (or maximize the number who didn't) and b) minimize the number of necessary assignments to MO.
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by Testluv » Thu Nov 12, 2009 11:47 pm
heshamelaziry wrote:What if the question asked for the maximum number. Would be different ?
At least 60% requested product development--so could be 100% (at least means anywhere from 60%-100%).

At least 65% need to be assigned to maintenance of old products--so could be 100% need to be assigned to maintenance of old products.

There is no cap on the fraction of engineers who requested product development, and there is also no cap on the fraction that must be assigned to maintenance of old products. All 200 could have wanted PD, and yet all 200 might have to get assigned to MO.

So, if the question were asking for the max, it would be all 200 of the engineers. However, in this situation, it makes a lot more sense for the test-maker to ask about minimum rather than maximum.

If the question had said "at most" wherever it said "at least" then it could have asked for the maximum.
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