For any graph such that y = f(x):
y = f(x) + k moves the graph UP k places.
y = f(x) - k moves the graph DOWN k places.
In the problem above, the graph of y = (x+1)(x-1)² has an x-intercept to the left (at x=-1) and an x-intercept to the right (at x=1).
Adding 2 to the function -- yielding y = (x+1)(x-1)² + 2 -- will move the graph UP 2 places.
When the graph moves up 2 places, the intercept to the right will disappear, leaving only the x-intercept to the left.
The correct answer is B.
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