Having trouble with is and I know it shouldbe simple.

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kschmudde: Newbie | Next Rank: 10 Posts; Posts: 2; Joined: Mon Mar 23, 2009 2:32 pm

by kschmudde » Mon Mar 23, 2009 3:18 pm

Can someone help me solve this;

1/4^m * 1/5^18 = 1/2(10^35)

solve for m

For some reason I cannot get my brain to break this down properly.

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Source: Beat The GMAT — Problem Solving | Mon Mar 23, 2009 3:18 pm

rs2010: Master | Next Rank: 500 Posts; Posts: 232; Joined: Fri Jul 04, 2008 4:14 pmFollowed by: 1 member; Thanked: 14 times; GMAT Score:760

by rs2010 » Mon Mar 23, 2009 5:16 pm

Compare the powers of 2.

1/4=(1/2)^2

Eqn will be

(1/2)^2m*(1/5)^18=(1/2)*(2^35)*(5^35)

2m=35-1
m=17

Last edited by rs2010 on Tue Mar 24, 2009 2:14 am, edited 1 time in total.

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KICKGMATASS123: Master | Next Rank: 500 Posts; Posts: 113; Joined: Thu Feb 26, 2009 8:13 am; Location: New Jersey; GMAT Score:650

by KICKGMATASS123 » Mon Mar 23, 2009 8:58 pm

It doesn't make sense..

How does 10^35 turn out to be 2^ (35*5*35)

Can you explain how u got that?

Thanks in advance

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rs2010: Master | Next Rank: 500 Posts; Posts: 232; Joined: Fri Jul 04, 2008 4:14 pmFollowed by: 1 member; Thanked: 14 times; GMAT Score:760

by rs2010 » Tue Mar 24, 2009 2:13 am

10=2*5

10^35=(2^35)* (5^35)

This is what I meant. That was typo.

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sacx: Master | Next Rank: 500 Posts; Posts: 139; Joined: Wed Oct 22, 2008 4:36 am; Thanked: 17 times

by sacx » Tue Mar 24, 2009 2:32 am

(1/4)^m (1/5)^18 = 1/2*10^35

using (ab)^m = a^m b ^m
a ^ m * a ^ n = a ^ m+n
(1/4)^m = (1/2)^2m

= (1/2)^2m (1/5)^18 = (1/2)^36 * (1/5)^35

Comparing on both sides

2m = 36

m = 18

SACX

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