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Having received his weekly allowance, John spent 3/5 of...

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by swerve » Fri Jan 12, 2018 1:53 pm
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Haveing received his weekly allowance, John spent 3/5 of his allowance at the arcade. The next day he spent one third of his remaining allowance at the toy store, and then spent his last $0.80 at the candy store. What is John's weekly allowance?

(A) $2.40
(B) $3.00
(C) $3.20
(D) $3.60
(E) $4.80

The OA is B.

Please, can any expert explain this PS question for me? I tried to solve it but I can't get the correct answer. I need your help. Thanks.
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by GMATWisdom » Fri Jan 12, 2018 2:48 pm
swerve wrote:Haveing received his weekly allowance, John spent 3/5 of his allowance at the arcade. The next day he spent one third of his remaining allowance at the toy store, and then spent his last $0.80 at the candy store. What is John's weekly allowance?

(A) $2.40
(B) $3.00
(C) $3.20
(D) $3.60
(E) $4.80

The OA is B.

Please, can any expert explain this PS question for me? I tried to solve it but I can't get the correct answer. I need your help. Thanks.
Assuming his weekly allowance is $15
First days expenditure= 15x3/5=$9. So remaining is 15-9=$6
next days expenditure at toy store =6x1/3=$2. So remaining for candy store is 6-2=$4
If $4 spent at candy store weekly allowance is $15
If $0.8 spent at candy store weekly allowance is=15x0.8/4=$3.0
Hence option B
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by Scott@TargetTestPrep » Tue Aug 06, 2019 4:33 pm
swerve wrote:Haveing received his weekly allowance, John spent 3/5 of his allowance at the arcade. The next day he spent one third of his remaining allowance at the toy store, and then spent his last $0.80 at the candy store. What is John's weekly allowance?

(A) $2.40
(B) $3.00
(C) $3.20
(D) $3.60
(E) $4.80

We can let n = the weekly allowance and create the equation:

(3/5)n + 1/3(2/5)n + 0.8 = n

3n/5 + 2n/15 + 0.8 = n

Multiplying by 15, we have:

9n + 2n + 12 = 15n

12 = 4n

3 = n

Answer: B

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