BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

gud n tuf ...ques..

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
Master | Next Rank: 500 Posts
Posts: 136
Joined: Sun Sep 28, 2008 8:20 pm
Location: fssf
Thanked: 17 times

by krazy800 » Tue Oct 07, 2008 1:33 am
is it 90.. OA PLZ
Aiming High
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 833
Joined: Mon Aug 04, 2008 1:56 am
Thanked: 13 times

by vivek.kapoor83 » Tue Oct 07, 2008 1:36 am
NO its not 90
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 833
Joined: Mon Aug 04, 2008 1:56 am
Thanked: 13 times

by vivek.kapoor83 » Tue Oct 07, 2008 3:11 am
here is the attachement of ques
Attachments
Untitled.jpg
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 871
Joined: Wed Aug 13, 2008 7:48 am
Thanked: 48 times

by stop@800 » Tue Oct 07, 2008 3:17 am
60 degree ?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 833
Joined: Mon Aug 04, 2008 1:56 am
Thanked: 13 times

by vivek.kapoor83 » Tue Oct 07, 2008 3:23 am
u r gem man..pls explain how
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 871
Joined: Wed Aug 13, 2008 7:48 am
Thanked: 48 times

by stop@800 » Tue Oct 07, 2008 3:38 am
BEG is a triangle formed by three diagonals of the cube.
All diagonals are equal in length so triangle would be equilateral
hence each angle is 60 degree.

I have incorrectly answered this questions twice so remember the answer :)

Edit reason: Corrected the typo.
Last edited by stop@800 on Wed Oct 08, 2008 1:11 am, edited 1 time in total.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 136
Joined: Sun Sep 28, 2008 8:20 pm
Location: fssf
Thanked: 17 times

by krazy800 » Tue Oct 07, 2008 3:48 am
Thanks stop 4 the explaination
Aiming High
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 833
Joined: Mon Aug 04, 2008 1:56 am
Thanked: 13 times

by vivek.kapoor83 » Tue Oct 07, 2008 4:15 am
that means.u also say its 90 degree bt ans is 60
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 136
Joined: Sun Sep 28, 2008 8:20 pm
Location: fssf
Thanked: 17 times

by krazy800 » Tue Oct 07, 2008 5:15 am
no Vivek i goofed it up.. so i thanked him for giving me a right answer n gud explaination..

thanks for the question though!
Aiming High
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 871
Joined: Wed Aug 13, 2008 7:48 am
Thanked: 48 times

by stop@800 » Wed Oct 08, 2008 1:10 am
there si a typo
Each angle will be 60 degree
by mistake I wrote 90 degree

I will correct my prev post....
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Newbie | Next Rank: 10 Posts
Posts: 2
Joined: Tue Aug 10, 2010 5:29 am

by parasarora » Tue Aug 10, 2010 5:31 am
according to me, the answer is 90 degrees. the line segment BE and EG lie in perpendicular planes.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Newbie | Next Rank: 10 Posts
Posts: 2
Joined: Mon Mar 16, 2009 3:56 am

by mastvita » Wed Oct 13, 2010 12:33 pm
I am opening this question again because I have a query.
Aren't diagonals of the square bisectors? If so each angle will be 45 and the ans should be 90?
Please explain...
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 12
Joined: Thu Aug 12, 2010 6:25 pm

by Viktri » Wed Oct 13, 2010 10:51 pm
mastvita wrote:I am opening this question again because I have a query.
Aren't diagonals of the square bisectors? If so each angle will be 45 and the ans should be 90?
Please explain...
B to E is diagonal on a face
so is BG and EG

Therefore, the 3 lengths are equal and they form an equilateral triangle, therefore the answer is 60
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1