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Senior | Next Rank: 100 Posts
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by vongdn » Wed Oct 06, 2010 7:56 pm
uIf x^4 + y^4 = 100, then the greatest possible value of x is between...

0 and 3
3 and 6
6 and 9
9 and 12
12 and 15


ANSWER --> 3 and 6

I get it so x^2 + y^2 = 10, but from there, now what?
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Master | Next Rank: 500 Posts
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by neerajkumar1_1 » Wed Oct 06, 2010 8:17 pm
the greatest possible value for x will be when y is minimum...

so let y=0, such that y^4 is min...

so x^4 = 100
now closest integer for x we get is 3, where 3^4 = 81 and is closest to 100...
4 will be bigger than 100...
Hence some non-integer value above 3 and less than 4 will give the greatest possible value...

hence x lies between 3 and 6

IMO: B
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