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Graphs point of intersectoin

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Source: — Problem Solving |

by camitava » Wed Nov 14, 2007 1:32 am
Gmatrant, as the line crosses the X-axis, so y = 0 and (x + a)(y + b) = 0
So x = -a and -b :- These are the points thru which that equ has passed thru X-axis. But we have to calculate the value of a and b. And that can be done by statement - 2. As, -6 = (0 + a)(0 + b) or ab = -6
And by statement - 1, a + b = -1
From these two questions, we can easily solve the values of a and b. So IMO C.
Correct me If I am wrong


Regards,

Amitava
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by gmatguy16 » Wed Nov 14, 2007 4:22 pm
agree with amit. ans c
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