I think your question has trivial answer if you will use the slope facts of y function. When slope=0 we have horizontal line (exclude this one). Here we are looking into sub-sector 0-90` where the slope is positively downward/upward (from the right upper corner to the left bottom corner). When the slope is 1, i.e. y=x we have 45` and in all other cases we have |y|>x. So by allowing 90-45=45 and 45/90 is 1/2 we may state the probability will be 1/2 that |y|>x. Additionally we can include the -ve function results in mode and state p=1/2 because the slope is mathematically a tangent of the angle in right triangle formed by x-coordinate line and the line |y|=x itself ---> delta(y)/delta(x).

all - Please ignore. I understood my mistake. there was an error in > and < sign.

answer is 3/4 thanks