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GPREP - Tricky funcion question

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by Sreema » Mon Nov 24, 2008 7:09 am
h(100) = 2*4*6*...100
= 2^50(1*2*3..50)

h(100) divisible by nos between 2 - 50
h(100)+1 not divisible by any nos including primes between 2 - 50 because the remainder will be 1.

so ans is E
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by vish150783 » Tue Dec 02, 2008 6:40 am
Sreema wrote:h(100) = 2*4*6*...100
= 2^50(1*2*3..50)

h(100) divisible by nos between 2 - 50
h(100)+1 not divisible by any nos including primes between 2 - 50 because the remainder will be 1.

so ans is E
yup i think E is the correct answer. BTW wasn' this a OG question. This also appears in the GMAT prep. Basic concept seems to be factoriziation.
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by Irena » Fri Dec 05, 2008 9:51 pm
How did you get 2^50? Thanx!
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2^50

by bbaah » Sun Dec 07, 2008 8:48 am
2*4*6*8*...*100 = (2*1)*(2*2)*(2*3)*(2*4)*...*(2*50)

= 2^50*(1*2*3*...*50)
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