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by jainnikhil02 » Wed Jun 08, 2011 11:05 am
When positive integer x is divided by positive integer y, the remainder is 9. If x/y = 96.12, what is the value of y?
A. 96
B. 75
C. 48
D. 25
E. 12

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by Frankenstein » Wed Jun 08, 2011 11:12 am
Hi,
0.12 = 9/y =>y = 75
Hence, B
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by champ0007 » Wed Jun 08, 2011 11:16 am
x/y = 96.12 = 96 + 0.12

Remainder comes from the decimal part of it

0.12y = 9

y = 9/0.12 = 900/12 = 300/4 = 75
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by smackmartine » Wed Jun 08, 2011 11:21 am
IMO B
x/y = 96.12
x=96 y + .12y

also x = yQ+9

from both statements 0.12y=9
y = 900/12 =75
Last edited by smackmartine on Wed Jun 08, 2011 11:35 am, edited 1 time in total.
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by champ0007 » Wed Jun 08, 2011 11:29 am
I think you meant "x = Qy + 9"
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by smackmartine » Wed Jun 08, 2011 11:34 am
champ0007 wrote:I think you meant "x = Qy + 9"
Yes.thnx
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by TuanNguyen87 » Wed Jun 08, 2011 2:35 pm
We have x/y = 96.12 => x = 96y + 0.12y
The remainder is 9,
=> 0.12y = 9 => y = 75
Answer: B
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by cans » Wed Jun 08, 2011 8:05 pm
When positive integer x is divided by positive integer y, the remainder is 9. If x/y = 96.12, what is the value of y?
x/y remainder=9
x/y=96.12
x=96.12y = 96y+.12y
thus x/y remainder = .12y=9
y=75
IMO B
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