At a local appliance manufacturing facility, the workers received a 20% hourly pay raise due to extraordinary performance. If one worker decided to reduce the number of hours that he worked so that his overall pay would remain unchanged, by approximately what percent would he reduce the number of hours that he worked? A) 83% B) 80% C) 20% D) 17% E) 12%

pradeepkaushal9518 wrote:At a local appliance manufacturing facility, the workers received a 20% hourly pay raise due to extraordinary performance. If one worker decided to reduce the number of hours that he worked so that his overall pay would remain unchanged, by approximately what percent would he reduce the number of hours that he worked? A) 83% B) 80% C) 20% D) 17% E) 12% product constancy. A * B = C if A gets increased by 1/5th (20%), B should be reduced by 1/6th (16.66%) to get C. {1+(1/5)} A * {1-(1/6)} B = (6/5) A * (5/6) B = A * B = C.

x be salary, h be old no. of hours H be new no. if hours xh=1.2xH H/h= 1/1.2 H/h = 83% That means new hours are 83 percent of old hours , hence old should be reduced by 17%

we can just use numbers to solve this because we are asked about the increase in percentage which should be true no matter what numbers we take old rate = $100/hr new rate = $120/hr old time = 6 hrs old wage = 6x100 = $600 new wage = $600 new time = 600/12 = 5 hrs percent reduction = 1/6 = 17%