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GMATPrep Test 1 - DS Sequence

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by medenica » Thu Jan 11, 2007 10:55 pm
If the terms of a squence are t1, t2, t3, ... , tn, what is the value of n?

1) The sum of the n terms is 3,124
2) The average of the n terms is 4

1 and 2 together are sufficient but can someone actually work out the problem? What are the formulas through which n is derived?
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by Argen » Thu Jan 11, 2007 11:17 pm
2) suggests that 4 = (sum of n terms) / n
1) states that (sum of n terms) = 3124
Therefore n = (sum of n terms) / 4 = 3124 / 4 = 781
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by medenica » Thu Jan 11, 2007 11:43 pm
Oh wow... how embarrassing. I was really complicating things - it's funny how missing what's being asked for does that...

tnx!
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by Scott@TargetTestPrep » Wed Jun 20, 2018 4:28 pm
medenica wrote:If the terms of a squence are t1, t2, t3, ... , tn, what is the value of n?

1) The sum of the n terms is 3,124
2) The average of the n terms is 4
We need to determine the number of terms in the sequence.

Statement One Only:

The sum of the n terms is 3,124.

Since we don't know anything about each individual term, we can't determine the number of terms in the sequence. Statement one alone is not sufficient.

Statement Two Only:

The average of the n terms is 4.

Since we don't know anything about each individual term, we can't determine the number of terms in the sequence. Statement one alone is not sufficient.

Statements One and Two Together:

Since sum = quantity x average, we have:

3,124 = n x 4

n = 3,124/4 = 781

Answer: C

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