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GmatPrep?? (Squared Inscribed)

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Re: GmatPrep?? (Squared Inscribed)

by sudhir3127 » Fri Aug 29, 2008 6:09 am
dferm wrote:Please Help...

Thanks.
its 6 pi

perimeter of a square is 4S

hence 4s = 24
s= 6

circumference of a circle is 2*pi*r

r is 6/2 = 3

2*pi*3 = 6 pi

hope that helps
Last edited by sudhir3127 on Fri Aug 29, 2008 10:57 am, edited 1 time in total.
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by mals24 » Fri Aug 29, 2008 6:28 am
IMO D

perimeter of a square =4s

4s=24
s=6

diameter of the circle T will be 6^2+6^2=d^2

72=d^2
hence d=6sqrt2

circumference of circle T pi D (or 2 pi r)

6sqrt2 pi
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by vishubn » Fri Aug 29, 2008 11:04 am
one more way

We know that the perimeter of the Square S is 24

which is a+a+a+a=24
4a=24
a=6 ( which is measurement of each side )
now the diagonal of the square is given by sqrt2*a

now it is 6 root 2

but radius = 3 root 2 and now circumference is 2 * pi * 3root2

6 pi root2 is the answer

Vishu
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