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by gmatsure76 » Sat Jul 12, 2008 5:20 am
can anyone tell me what is the easiest method to solve this kind of problem
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Source: — Data Sufficiency |
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by target790 » Sat Jul 12, 2008 11:57 am
Let W,C,M represent women,children,men.

W/C=5/2
=>W=5C/2


1>

C/M=5/11

=>M = 11C /5
Clearly not sufficient due to lack of values for W or C at this stage.


2>

W <30
= 5C /2 <30
= C < 12

Not sufficient too .


Combine both.

M = 11C /5 where C < 12
So C can be 5 or 10

So combination doesn't helps either.



So option E is correct.
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by Amitk101 » Sat Jul 12, 2008 11:26 pm
A small correction.

W/C=5/2
C=2W/5

C/M=5/11
M=11C/5

M=(11/5)*(2W/5)
M=22W/25

As w<30, only 1 value is possible and that is 25.
So C should be the answer.
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OA

by ektamatta » Sun Jul 27, 2008 5:59 am
What is the OA?
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by ildude02 » Sun Jul 27, 2008 7:41 am
target790 wrote:Let W,C,M represent women,children,men.

W/C=5/2
=>W=5C/2


1>

C/M=5/11

=>M = 11C /5
Clearly not sufficient due to lack of values for W or C at this stage.


2>

W <30
= 5C /2 <30
= C < 12

Not sufficient too .


Combine both.

M = 11C /5 where C < 12
So C can be 5 or 10

So combination doesn't helps either.



So option E is correct.
You got it all correct , but C cannot take a value of 5 since W=5C/2 will not give us an integer. So C can only be 10 to give integer values for W and M.

C should be the answer.
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