BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Gmatprep rates

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Senior | Next Rank: 100 Posts
Posts: 80
Joined: Fri Apr 13, 2007 7:02 am
Location: Long Island
by maolivie » Fri Jul 13, 2007 3:20 pm
A hiker walking at a constant rate of 4 miles per hour is passed by a cyclist travelling in the same direction at t he rate of 20 miles per hour. The cyclist stops to wait for the hiker 5 minutes after passing her. While the hiker continues to walk at her constant rate, how many minutes must the cyclist wait until the hiker catches up?

1- 6 2/3
2- 15
3- 20
4- 25
5 - 26 2/3

I keep getting 2 even after converting the rates to minues. OA is C.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
User avatar
Community Manager
Posts: 789
Joined: Sun Jan 28, 2007 3:51 pmFollowed by: 1 member
Location: Silicon valley, California
Thanked: 30 times

Re: Gmatprep rates

by jayhawk2001 » Fri Jul 13, 2007 3:30 pm
The speed of the cyclist relative to the hiker = 20-4 = 16 mph

Since the cyclist travels for 5 min after passing the hiker, the
distance traveled by the cyclist = 16 * 5 / 60 miles

This distance can be traveled by the hiker in 16 * 5/60 * 1/4
= 20/60 hrs = 20 min
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 80
Joined: Fri Apr 13, 2007 7:02 am
Location: Long Island

by maolivie » Fri Jul 13, 2007 3:37 pm
where did the 60 in the denominator to 5/60 come from?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Community Manager
Posts: 789
Joined: Sun Jan 28, 2007 3:51 pmFollowed by: 1 member
Location: Silicon valley, California
Thanked: 30 times

by jayhawk2001 » Fri Jul 13, 2007 3:50 pm
maolivie wrote:where did the 60 in the denominator to 5/60 come from?
All 'rate' values are in miles per "hour". So, you either have to convert
rates to miles per minute OR convert time from minutes to hour for
proper calculation

We are given that the cyclist travels 5 minutes i.e. 5/60 hours.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Newbie | Next Rank: 10 Posts
Posts: 1
Joined: Tue Dec 19, 2006 7:31 am
Location: Boston, MA

by perpetual_stud » Mon Jul 16, 2007 9:40 am
Hello Guys,

I am new to the forum.

The biker passes the hiker and bikes for another 5 mins. So the distance traveled by biker is 5/3 miles in 5 mins.

The time that the biker is biking for 5 mins, the hiker is walking to so you have to take into acct the distance the hiker travels in 5 mins.

In 5 mins the hiker travels 1/3 miles. So the distance traveled by the hiker after the biker stops is 5/3 – 1/3 = 4/3.

The time the biker has to wait is therefore 4/3/4 = 4/12 = 1/3.
So the biker has to wait 1/3 hour which is equal to 1/3 X 60 = 20 mins.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1