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GMATPrep question

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rajesh_ctm Master | Next Rank: 500 Posts Default Avatar
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GMATPrep question

Post Thu Apr 26, 2007 8:11 pm
How to approach these types?
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jayhawk2001 Community Manager
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Post Thu Apr 26, 2007 10:19 pm
Plugging in values might be your best bet here.

Have a sorted list in increasing order i.e.

B C D E A F

1 - Insufficient. A = 41 or F = 41 (only 2 possibilities).
If A = 41, yes > 10
If F = 41, the list can be "4 6 7 8 9 41" or "2 6 7 8 11 41"
So insufficient.

2 - Insufficient. List can be same as in 1 i.e. "4 6 7 8 9 41" or
"2 6 7 8 11 41". There are numerous possibilities

Using 1 and 2, we still cannot arrive at a unique value (well we have
already done it as part of B above).

So E

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rajesh_ctm Master | Next Rank: 500 Posts Default Avatar
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Post Thu Apr 26, 2007 8:44 pm
Yes, it is E.

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f2001290 Master | Next Rank: 500 Posts
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Post Thu Apr 26, 2007 8:42 pm
What is the solution ? Is it "E"

If you can confirm the solution, I can tell the approach.

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