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by mlane25269 » Sun Jun 22, 2008 4:01 pm
How do I solve? Thanks!
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by niraj_a » Sun Jun 22, 2008 4:02 pm
3 should be the answer

i solved this by drawing a simple diagram...
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by mlane25269 » Sun Jun 22, 2008 4:07 pm
How did get 3 for the answer? I drew a diagram also but my diagram shows more than 5 oranges being in the top row and that's not even one of the answer choices!!
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by beeparoo » Sun Jun 22, 2008 4:24 pm
mlane25269 wrote:How did get 3 for the answer? I drew a diagram also but my diagram shows more than 5 oranges being in the top row and that's not even one of the answer choices!!
@mlane: Hmmm... Let me pick your brain a bit. How many oranges did you have in your 2nd (middle) layer?

Sandra
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by mlane25269 » Sun Jun 22, 2008 9:10 pm
I came up with 8 oranges in the second row for my drawing
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by beeparoo » Mon Jun 23, 2008 9:17 am
mlane25269 wrote:I came up with 8 oranges in the second row for my drawing
OK - I had 8 oranges too and I still got the correct answer, which is 3 oranges on the 3rd layer (very top).

Assuming your 2nd layer looks like this rough sketch:
OOOO
OOOO

Then only 3 oranges can be stacked on top while satisfying the condition in the Question-Stem.

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mlane25269 wrote:How did get 3 for the answer? I drew a diagram also but my diagram shows more than 5 oranges being in the top row and that's not even one of the answer choices!!
How did you manage to stack another 8 oranges on the top 3rd layer layer without breaking the condition?
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by mlane25269 » Mon Jun 23, 2008 10:32 am
ok I think I know what I did wrong now. I drew the second layer outside of my original drawing and came up with 3 oranges staced on top of the second row. Makes sense now. Thanks!
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by ksh » Mon Jun 23, 2008 10:19 pm
Hi,

the bottommost 3 rows will have 5*3=15 oranges
Second stack will have 4*2 =8 oranges and,
the topmost stack will have just 3*1=3 oranges.

Hope this makes a sense.
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by mlane25269 » Mon Jun 23, 2008 11:28 pm
ok that makes sense now! thanks!
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