GMATPrep Qn.

Here is the explanetion:

Statement 1 - CO=BO so angle BCO=CBO=40. CA is the lineand has 180 grades, so angle OBA is 140, finally since OB=BA BOA=BAO=(180-40)/2 = 20
Statement 2 - since BCO is 40 degrees and has equall legs so OBC is also 40 degrees. As a result ABO is 140 degrees and AB equals with radius, so AB=BO, AOB=BAO and = 20 (since all three angles sum is 180)

I still don't get the explanation for statement 1. Given COD=60 degees, how did you arrive at OCB=OBC=40 degrees??

Pavithra

Yo ppl....this problem is killing me. could anyone please help.

Pavithra

what we know: cbo = bco (isoscles triangle).
bao = boa (isocles triangle).

(1) we know that cbo = 2bao b/c of the the external angle rule.
120 = bao + (180-2cbo) ; cbo = 2bao.
120 = bao + (180 -4bao)
3bao = 60; bao = 20. So (1) is sufficient.

(2) much easier to solve; bco = 2 bao
40 = 2bao; bao = 20

Thanks a lot...that was eally helpful.

Pavithra