it seems i am giving a prep...

Okie.. let me try this one...

You got this questin wrong big time...!!!

2> 6y2 + 41y + 25
even + odd + 41y
odd + odd*y = even
y has to be odd

but we can't deduce anything from this about x ..
insuff

1. x ( y+ 5) = even

y is even then x has to be odd
y is odd then x can be anything
hence insuff

combining both 1 & 2
x * even = even
so x can be both odd and even

Hence IMO E

Given : x and y are integers

Q: Is x even

Stmt I

Rules:

even * odd = even
odd * even = even


x ( y+5) is even {even * odd = even or odd * even = even}

case 1:

x-> odd y+5 > even i.e y->odd

x->even y can be odd or even still x(y+5) will be even

INSUFF

Stmt II

Rules:

odd+odd = even
even + even = even

6y^2 + 41y + 25 - >even

6y^2 is always even since even * odd or even*even are both even so we cant say anyhting about y yet if its even or odd However 6y^2+41y combined has to be odd since only odd + 25(odd) - >even i.e 41y has to be odd and y has to be odd since 41 is odd and if y was even 41*y would be evn and not odd based on the rules above

All we know is y is odd x could still be even or odd

INSUFF


Stmt I and II together

y->odd y+5 is even so no matter what x (X COULD BE ODD OR EVEN) is x(y+5) will always be even based on rules in bold above

INSUFF


Choose E)


P.S : I know there are lots of even's and odd's in the explanation so let me know if u still have questions...

Good luck!

Regards,
Cramya

Thnaks

C for me as well.
Couldnt have explained better than Ronnie and Cramya.
So I rest my case