cramya wrote:Lets make it easier. Picking smart numbers works wonders for this problem and the computations dont take long.
zt < -3 Is z < 4
Stmt I
z<9
z= 8 t=-1000 zt < -3 z<4 NO
z=1 t= -1000 zt<-3 z<4 YES
INSUFF
Stmt II
t < -4 (Use same example)
z= 8 t=-1000 zt < -3 z<4 NO
z=1 t= -1000 zt<-3 z<4 YES
INSUFF
Together
Same example again no need to pick new numbers
ISNUFF
Choose E)
Cramya,
IMO Stmt 1 is very very straight forward and does not need any calc at all.
z < 9. so z can be 8.99,.. 8, 7.... minus infinity. So some are >4 and others are < 4 and 1 of them =4. So insufficient.
So I really dint have to substitute into zt and then figure out.
is my reasoning right ??
When I saw this stmt, I thought that I am seeing a very very simple stmt, and the test makers hope that the test takers, with all their preparation for tough questions, will make this stmt unnecessarily complicated and spend time trying to solve it, thereby killing time. And this is what test makers want!!!.
Do u folks also think that stmt 1 is in the above category??
thanks