GMATPrep PS Questions Help

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myfish: Senior | Next Rank: 100 Posts; Posts: 67; Joined: Mon May 03, 2010 12:03 pm; Thanked: 3 times

by myfish » Wed Sep 21, 2011 8:15 pm

I am struggling to find answers for the GMATPrep questions on BTG and anywhere else. My search returns all kinds of stuff but not the answers for the questions I am looking for. If there is a book I can buy I am more than happy to get all the answers, until then it would be great to see how to solve these. Thanks so much.

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Source: Beat The GMAT — Problem Solving | Wed Sep 21, 2011 8:15 pm

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Anurag@Gurome: GMAT Instructor; Posts: 3835; Joined: Fri Apr 02, 2010 10:00 pmFollowed by: 523 members; Location: Milpitas, CA; Thanked: 1854 times; GMAT Score:770

by Anurag@Gurome » Wed Sep 21, 2011 8:39 pm

All of the stocks on the over the counter market are designated by either a 4 letter or a 5 letter code that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different stocks that can be designated with these codes?

Maximum number of stock codes = possible number of 4 letter codes + possible number of 5 letter codes
A 4 letter code can be _ _ _ _, where 1st position can be any one of the 26 letters, similarly 2nd position can be one of the 26 letters, and the same applied for 3rd and 4th positions.
So, possible no. of 4 letter codes = 26 * 26 * 26 * 26 = 26^4
In the same way, possible no. of 5 letter codes = 26 * 26 * 26 * 26 * 26 = 26^5

Therefore, maximum number of stock codes = 26^4 + 26^5 = 26^4(1 + 26) = 27(26^4)

The correct answer is C.

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cans: Legendary Member; Posts: 1309; Joined: Mon Apr 04, 2011 5:34 amFollowed by: 123 members; Location: India; Thanked: 310 times; GMAT Score:750

by cans » Wed Sep 21, 2011 8:46 pm

Answer to the 1st one:
[9] = 3*9 = 27 (as 9 is odd)
[6] = 6/2 = 3 (as 6 is even)
Thus answer should be 27*3=81
now [81] = 3*81 !=81
and [27] = 3*27 = 81
thus answer is [27]
IMO D

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Cans!!

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GMAT/MBA Expert

Anurag@Gurome: GMAT Instructor; Posts: 3835; Joined: Fri Apr 02, 2010 10:00 pmFollowed by: 523 members; Location: Milpitas, CA; Thanked: 1854 times; GMAT Score:770

by Anurag@Gurome » Wed Sep 21, 2011 8:47 pm

For which of the following functions is f(a + b) = f(a) + f(b) for all positive numbers a and b?

(A) f(x) = x^2
(B) f(x) = x+1
(C) f(x) = âˆšx
(D) f(x) = 2/x
(E) f(x) = -3x

Let's analyze each of the options individually:

1. (a + b)Â² â‰ (aÂ² + bÂ²) => f(a + b) â‰ f(a) + f(b)
2. (a + b + 1) â‰ (a + 1) + (b + 1) = (a + b + 2) => f(a + b) â‰ f(a) + f(b)
3. âˆš(a + b) â‰ (âˆša + âˆšb) => f(a + b) â‰ f(a) + f(b)
4. 2/(a + b) â‰ (2/a) + (2/b) = 2(a + b)/ab => f(a + b) â‰ f(a) + f(b)
5. (-3(a + b)) = (-3a) + (-3b) => f(a + b) = f(a) + f(b)

The correct answer is E.

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myfish: Senior | Next Rank: 100 Posts; Posts: 67; Joined: Mon May 03, 2010 12:03 pm; Thanked: 3 times

by myfish » Wed Sep 21, 2011 10:09 pm

Thank you soo much! So quick!!! In the middle of the night! Unbelievable!

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