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GMATprep PS question

Expert replies
by mlane25269 » Sat Jul 19, 2008 1:35 pm
Hi! Can someone explain this question? Thanks!
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Source: — Problem Solving |

by Jgerard » Sat Jul 19, 2008 3:50 pm
I believe the answer is

1/2 (base)(height)= Area

1/2 (4)(y-intercept) = 12

4(y-intercept) = 24

y-intercept must be -6 because slope of line is positive and crosses the x axis at positive 4. Therefore y intercept must be negative.
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by john1234 » Sat Jul 19, 2008 5:18 pm
believe the answer is

1/2 (base)(height)= Area

1/2 (4)(y-intercept) = 12

4(y-intercept) = 24

y-intercept must be -6 because slope of line is positive and crosses the x axis at positive 4. Therefore y intercept must be negative


How can Y- intercept be negative when the slope is positve and X-intercept is potive(4)?.

Slope Y2-Y1/X2-X1 can only be +ve if Y2 -Y1 is posive and X2-X1 is positve or Y2-Y1 is negative and X2 - X1 is negative.I think Y intercept is + 6.
Even impossible says I M possible
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by Mclaughlin » Sat Jul 19, 2008 9:40 pm
What's the OA?
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by mlane25269 » Sun Jul 20, 2008 10:20 am
I believe the OA is e) 6 but sorry I didn't get a screenshot of it. I picked 3 which was obviously wrong.
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by pepeprepa » Sun Jul 20, 2008 10:26 am
Just draw it, the answer is -6
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by asigheartau » Sun Jul 20, 2008 12:41 pm
bearing in mind the slope is positive and we know the x intercept to be 4( so positive), the slope has to be in the first quadrant in order to be positive.

Hence, slope is [change in Y/ change in X]. Knowing the x intercept, we know that change in y / 4= a positive number for the slope.
for points (0, y) and (4,0)

Slope: 0-y/4-0 must be positive
-y/4>0 => y needs to have a negative value
A of triangle formed by k is 12 => sides are 4 and 6

X intercept 4,0
Y intercept 0, -6
Last edited by asigheartau on Mon Jul 21, 2008 7:12 pm, edited 1 time in total.
Alin Sigheartau
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by pepeprepa » Sun Jul 20, 2008 1:38 pm
I think the positive slope argument is wrong.

Let's agree about that: A(4;0) B(0;x)
We know the slope has to be positive.
Thanks to the slope formula "Slope=(y-b)/(x-a) for C(x;y) and D(a;b)" let's see what happens when the answer is "6".

"Slope which must be positive"=(0-6)/(4-0)=-6/4 and -6/4<0

Answer is -6.
Tell me if I'm wrong.
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by Canman » Mon Jul 21, 2008 4:24 am
If y intercept is positive then it violates one of the two restrictions in the question stem:

1) triangle is formed by k and the TWO axes
2) k has a positive slope

I agree with -6 as the answer unless someone can illustrate how +6 can coexist with statements from the stem.
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by asigheartau » Mon Jul 21, 2008 7:05 pm
agreed with you, pepeprepa

The slope has to be positive in order to satisfy the dates of the problem=> y intercept is -6.

Disregards the previous post. Pepeprepa is right
Alin Sigheartau
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