Folks, can anyone take a crack at this :
If xy =1, what is [2(x+y)^2]/[2(x-y)^2] ?
The answer is 16 somehow.. :s
If xy =1, what is [2(x+y)^2]/[2(x-y)^2] ?
The answer is 16 somehow.. :s
Deb
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Ah- they could both be 1, but they don't both need to be 1. They could both be -1, for example, or x could be 1/2 and y could be 2.niraj_a wrote: b) since x * y = 1, then both have to be 1